News from MAST
Well, I am finally getting
this column out; I only hope it gets in on time.
We have acquired some new equipment here: A Mettler Toledo AB104 analytical
balance, an HP 8450A Spectrophotometer (!), an old, but working, a
CAPCO model 700 gas chromatograph, an incubator, several glass petrie
dishes, and both nutrient broth and nutrient agar (for microbiology
experiments). We are actually doing experiments in colorimetry and
should have some reports for the Bulletin in the not too distant future.
Symmetry Groups
As promised I am going
to talk about symmetry groups (a little late, but what the hey). In
a previous column, (print version only) "The More Things Change, The
More Some Things Stay the Same," I described the importance of conservation
laws. When some physical property is conserved then its behavior is
symmetrical with respect to certain relations involving the physical
property. The trick is, of course, to find these. We can use groups
to help us.
For example, if we assume
the shape of an equilateral triangle to be conserved (i.e. the distance
between points never changes) then we would expect certain motions
about the center of the triangle to be symmetrical. Let us look at
such a triangle,

here we have labeled the
vertices {1, 2, 3}, we will label this arrangement
.
If we rotate the triangle 120° the triangle will still look roughly
the same and we then get this arrangement with the vertices now at
{2, 3, 1}, we will label this
.

Here we perform another
such rotation we get the vertices {3, 1, 2}, we will call this
.

If we imagine a line extending
from 1 to the midpoint of the segment 23, then we switch 2 and 3 we
get the vertices {1, 3, 2} and we will call this
.

If we rotate the triangle
and then perform another reflection we get the vertices {2, 1, 3}
and we call this
.

Finally, if we rotate the
triangle twice and perform another reflection we get the set of vertices
{3, 2, 1}and we call this
.
We now have all of the
vertices for various rotations and reflections. We will see if this
forms a groups or not. Each combination of vertices forms an element
of the set of orientations of our triangle. We will now construct
a table of how each operation acts upon an initial orientation. We
begin with
as
our initial orientation. If we simply apply our initial orientation
(no operations) we get
again.
If we rotate by 120° we get
,
and so on. If we go through and perform all operations on all of the
possible initial configurations we get the following table (called
a Cayley Table).

It is fairly easy to just
look at the table and see that every operation yields an element of
the set (thus the set is closed under the rotations and reflections).
I leave it to you to show that the operations are associative (though
this too is easily seen from the table). The identity operation is
.
I leave it as an exercise to you to show that there is an inverse
to every operation resulting in
.
Under these properties this forms a group.
Question: Is this group
commutative?
What reveals symmetry are
those operations that leave the set unchanged. We begin with
and
we apply a 120° rotation to get
.
Now we have
and
we apply a 240° rotation
and
we get
.
In a like fashion we can study all possible combinations that lead
to our starting point, whatever configuration that is. This gives
us a clue to what is conserved, since the only things not changing
are the distances between the points, we would guess (even if we had
not know this already) that the length of the segments remain unchanged.
A Note in Thanks
I would like to thank Allen
Hubbard and Kenneth Levasseur for their work with Mathematica
in gneeral and their excellent book Exploring Abstract Algebra
with Mathematica, this was the inspiration for most of
the illustrations and their software was used throughout. This book
is published by TELOS a Springer-Verlag imprint (1999).
A Note About MAST Courses
MAST is currently offering
courses in Self-Study, The Conduct of Science, and Scientific Writing.
Over the next month lessons for the Basic Mathematics I and II courses
will appear and I hope to have some lessons for the Basic Calculus
course by the end of September. Beginning with the Basic Mathematics
I course Wolfram Research (the makers of Mathematica) will
be making a special offer to all SAS members who officially register
for courses using Mathematica: A free six-month license will
be issued to any member who takes such a course, those who take multiple
courses will be treated as full-time students and will be allowed
to buy the student version of Mathematica for only $140 (this
is identical to the professional version, without the big reference
books and with no technical support) and the ability to upgrade to
the professional version for $350 later on (a total of $490, pretty
good when you consider Mathematica retails for $1,200).
For Those of You on a
Budget
Wolfram Research has just
released the Mathematical Explorer, a subset of Mathematica
that costs less than $80. I have just received my copy and will write
a detailed review when I get a chance. My immediate impression is
that it is very nice. 
Converted by Mathematica
August 29, 2001